Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.
Construct a ∆XYZ in which angle Y = 30°, angle Z = 90° and XY+ YZ+ZX= 11 cm.
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ
Construct a triangle xyz in which angle y=30°, z=90°andxy + yz + zx = 11cmgrd 9 Ch-constructionsI have
Construct a triangle XYZ in which \[\angle Y = {30^ \circ },\angle Z = { 90^ \circ }\,and\,XY + YZ + ZX = 11\,cm\].
CONSTRUCT A TRIANGLE XYZ IN WHICH ANGLE Y = 30, Z = 90 AND XY + YZ + ZX = 11CM
Construct A Triangle XYZ In Which ∠Y = 30°, ∠Z = 90° And XY+YZ+ZX = 11 cm, Class 9
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm class 9 ex 11.2 Q4
Construct a triangle XYZ in which angleY=30^@ , angleZ=90^@ and XY +
4. Construct a triangle XYZ in which ∠Y=30∘,∠Z=90∘ and XY+YZ+ZX=11 cm
construct a triangle xyz in which angle Y is equal to 30 degree angle Z is equal to 90 degree and XY + YZ+
Class 9 NCERT Solutions- Chapter 11 Constructions - Exercise 11.2 - GeeksforGeeks
cbse-ncert-9th-class-Chapter-12-Constructions